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Bus Discussion => Bus Topics ( click here for quick start! ) => Topic started by: Ncbob on September 17, 2006, 03:50:10 PM

Title: LED info proved absolutely correct.....
Post by: Ncbob on September 17, 2006, 03:50:10 PM
So, I wish to extend my thanks to both BoogietheCat and Gumpy for their offerings.

I tested the LED tail and turn signal lamps I purchased from the e outfit (knowing that Ohm's Law would prevail) but the explanations of these two gentlemen made my testing a whole lot easier.

So, when we show up in Timmonsville next month we'll be safety protected with the new lamps on the rear of our bus.  Sometime this winter we'll tackle the fronts but thought I'd take this opportunity to thank these two for their in depth research and finding a way to convey the results to the lesser able of us.

NCbob
Title: Re: LED info proved absolutely correct.....
Post by: NJT5047 on September 17, 2006, 07:23:38 PM
Bob, while you're in 'Ohm's Law" mode, would you figger what size resistor(s) it would take to operate an 1157 12V automotive tail light bulb with 24V.    Take two for each bulb...running light filament and the brake light filament.  I don't remember how to do this...if I had the formula...maybe..    
I spent several hours the other day driving from parts store to ....trying to fnd 24V bulbs.  No find.  NAPA can get them, but not until next week.   My bus doesn't use any 24V tail light bulbs...all the rear lights appear to be "sealed beam" thingies.  The brake light may not be...but the turn and tail lights are definitely sealed beams. ...or sealed lights.   The whole light pops out and a new one pushes in.  Keeps the lenses looking new!   Quick to change if the little plug cooperates. 
Thanks in advance! JR
Title: Re: LED info proved absolutely correct.....
Post by: Dallas on September 17, 2006, 08:20:08 PM
JR,

Ohms Law:

e=IXR
I=E/R
R=E/I

Title: Re: LED info proved absolutely correct.....
Post by: chargePlus on September 17, 2006, 08:52:19 PM
Quote from: Dallas on September 17, 2006, 08:20:08 PM
JR,

Ohms Law:

e=IXR
I=E/R
R=E/I

The way I learned in in college a few years ago, with the circle drawn out as in Dallas' post, cover up what you are looking to find and the remaining two will be in the proper orientation of either a division or multiplication equation.

- John